Ableitungen Produkt- und Kettenregel
in Frage&Antwort
© bGeiring hGeiring v12 2013
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`f(x) = x^2*e^(-3x)`
1. Ableitung?
`f´(x) = 2x*e^(-3x) + x^2*(-3)*e^(-3x)`
`= x*e^(-3x)*(2-3x)`
`u(x) = x^2` `u´(x) = 2x`
`v(x) = e^(-3x)` `v´(x) = -3*e^(-3x)`
`f(x) = x^2*sin(-3x)`
1. Ableitung?
`f´(x) = 2x*sin(-3x)+x^2*(-3)*cos(-3x)`
`= x*(2sin(-3x) - 3x*cos(-3x))`
`u(x) = x^2` `u´(x) = 2x`
`v(x) = sin(-3x)` `v´(x) = -3*cos(-3x)`
`f(x) = (x+e^x)^2`
1. Ableitung?
`f´(x) = 2*(x+e^x)*(1+e^x)`
`f(x) = (u(x))/(v(x))`
1. Ableitung?
`f(x) = u(x)*(v(x))^-1`
`f´(x) = u´(x) * (v(x))^-1 + u(x)*(-(v(x))^-2)*v´(x)`
`= (u´(x))/(v(x)) - (u(x)*v´(x))/(v(x))^2`
`= (u´(x)*v(x) - u(x)*v´(x))/(v(x))^2` (Quotientenregel)
`f(x) = (x+1)/e^x`
1. Ableitung?
`f(x) = (x+1)*e^(-x)`
`f´(x) = 1*e^(-x) + (x+1)*(-e^(-x))`
`u(x) = x+1` `u´(x) = 1`
`v(x) = e^(-x)` `v´(x) = -e^(-x)`
`f(x) = u(x)*(v(x))^2`
1. Ableitung?
`f´(x) = u´(x)*(v(x))^2 + u(x)*2v(x)*v´(x)`
`= v(x)[u´(x)*v(x)+2u(x)*v´(x)]`
`f_a(t) = a(t-15)e^(-0,01t) + a*15`
1. Ableitung?
`f_a´(t) = a*e^(-0,01t)+a(t-15)*(-0,01e^(-0,01t))`
`= a*e^(-0,01t)*(1-0,01t+0,15)`
`u(t) = a(t-15)= a*t-a*15` `u´(t) = a`
`v(t) = e^(-0,01t)` `v´(t) = -0,01e^(-0,01t)`
`f(x) = 1/(1+x^2)`
1. Ableitung?
`f(x) = (1+x^2)^(-1)`
`f´(x) = -(1+x^2)^(-2)*2x`
`= (-2x)/(1+x^2)^2`
`f_t(x) = sin(tx) + 2`
1. Ableitung?
`f_t´(x) = t*cos(tx)`
`f_k(x) = k*e^(kx)-8`
1. Ableitung?
`f_k´(x) = k^2*e^(kx)`