Binomische Formeln 1
in Frage&Antwort
© bGeiring hGeiring v12 2013
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`(a+b)^2 = ? `
`= a^2 + 2ab + b^2`
`(a+19)^2 = ? `
`= a^2 + 38a + 361`
`(x+7)^2 = ? `
`= x^2 + 14x + 49`
`(b+a)^2 = ? `
`= b^2 + 2ab + a^2`
`(y+x)^2 = ? `
`= y^2 + 2xy + x^2`
`(a+15)^2 = ? `
`= a^2 + 30a + 225`
`(4+a)^2 = ? `
`= 16 + 8a + a^2`
`(x+5)^2 = ? `
`= x^2 + 10x + 25`
`(16+x)^2 = ? `
`= 256 + 32x + x^2`
`(y+x)(y-x) = ? `
`= y^2 - x^2`
`(b+a)(b-a) = ? `
`= b^2 - a^2`
`(x+13)^2 = ? `
`= x^2 + 26x + 169`
`(a-2)(a+2) = ? `
`= a^2 - 4`
`(7+a)(a-7) = ? `
`= a^2 - 49`
`(7+a)(7-a) = ? `
`= 49 - a^2`
`(a-b)^2 = ? `
`= a^2 - 2ab + b^2`
`(d^2-1)/(1-d^2) = ?`
`= (-(1-d^2))/(1-d^2)`
`= -1`
`(x+y)/(x-y) = ?`
ist nicht kürzbar.
`(11+x)^2 = ? `
`= 121 + 22x + x^2`
`(a+b)(a-b) = ? `
`= a^2 - b^2`
`(a-13)^2 = ?`
`= a^2 -26a + 169`
`(6+a)(6-a) = ? `
`= 36 - a^2`
`(a^2-1)/(a+1) = ?`
`=((a +1)*(a-1))/(a+1)`
`= a-1`
`(a-b)/(b-a) = ?`
`= (a-b)/(-(a-b))`
`= -1`
`(9+x)(x-9) = ?`
`= x^2 - 81`
`(b^3-bc^2)/(b+c) = ? `
`= (b*(b^2-c^2))/(b+c)`
`= (b*(b+c)*(b-c))/(b+c)`
`= b*(b-c)`
`(10+a)(10-a) = ? `
`= 100 - a^2`
`(19+u)^2 = ? `
`= 361 + 38u + u^2`
`((a+b)^2)/(a+b) = ?`
`= a+b`
`(b^2 +1)/(b^2-1) = ?`
ist nicht kürzbar
`(x^2 + 2xy + y^2)/(x+y) = ?`
`= ((x+y)*(x+y))/(x+y)`
`= x+y`
`(a^2 - b^2) / (a-b) = ?`
`= ((a+b)(a-b))/(a-b)`
`= a+b`
`(a^2 + b^2)/(a^2-b^2) = ?`
ist nicht kürzbar.
`((c+d)^2)/(c^2-d^2) = ?`
`= ((c+d)*(c+d))/((c+d)*(c-d))`
`= (c+d)/(c-d)`
`(u^3-uv^2)/(u^2+uv) = ? `
`= (u*(u^2-v^2))/(u(u+v))`
`= (u^2-v^2)/(u+v)`
`= ((u+v)*(u-v))/(u+v)`
`= u-v`
`(1-a^2)/(a+1) = ?`
`=((1-a)*(1+a))/(1+a)`
`= 1-a`